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2021-01-08 Expected Value shark 1 min read

Q: What is the expected value if the die is reweighted so that 6 occurs half the time?

$E(X) = 6 \times \frac{1}{2} + \frac{1}{10} \times \frac{(1+5) \times 5}{2} = 4.5$

Q: What would the expected value be if the 6 is replaced by a 12?

$E(X) = 7.5$

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