Swift solution
/**
* Definition for a binary tree node.
* public class TreeNode {
* public var val: Int
* public var left: TreeNode?
* public var right: TreeNode?
* public init() { self.val = 0; self.left = nil; self.right = nil; }
* public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }
* public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {
* self.val = val
* self.left = left
* self.right = right
* }
* }
*/
class Solution {
func invertTree(_ root: TreeNode?) -> TreeNode? {
// tree exits?
guard let root = root else {
return nil
}
let left: TreeNode? = invertTree(root.left)
let right: TreeNode? = invertTree(root.right)
root.left = right
root.right = left
return root
}
}